### Do You Find Expert For Wireless Data Link Assignment Help? Want To Score High In Academics? Come To Us At Expertsminds!

Home   Course
Previous << || >> Next

NEVER LOSE YOUR CHANCE TO EXCEL IN WIRELESS DATA LINK ASSIGNMENT - HIRE BEST QUALITY TUTOR FOR ASSIGNMENT HELP!

Question 1: Calculate the FSPL in dB for a distance of 5Km and 10 Km for two different frequencies 5.8GHz, 2.4GHz and construct a table.

Answer: Given Distance d= 5 km

Given Frequency f=2.4 GHZ

when the distance (d is in km) and the frequency (f is in MHz) , the following formula is used to calculate the FSPL

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45 (1)

The given frequency is in GHZ, so we have to convert it in MHZ to use the above formula,

Frequency=2400 MHZ

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45

Substitute value of frequency and distance in equation (1),we get

FPSL(dB) = 20log10(5) + 20log10(2400) + 32.45

FPSL= 114.0336 dB.

Given Distance d= 5 km

Frequency f=5.8 GHZ

when the distance (d is in km) and the frequency (f is in MHz) , the following formula is used to calculate the FSPL

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45 (1)

The given frequency is in GHZ, so we have to convert it in MHZ to use the above formula,

Frequency=5800 MHZ

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45

Substitute value of frequency and distance in equation (1),we get

FP(dB) = 20log10(d) + 20log10(f) + 32.45

FP(dB) = 20log10(5) + 20log10(5800) + 32.45

FPSL= 121.698 dB.

Given Distance d= 10 km

Frequency f=2.4 GHZ

when the distance (d is in km) and the frequency (f is in MHz) , the following formula is used to calculate the FSPL

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45 (1)

The given frequency is in GHZ, so we have to convert it in MHZ to use the above formula,

Frequency=2400 MHZ

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45

Substitute value of frequency and distance in equation (1),we get

FP(dB) = 20log10(d) + 20log10(f) + 32.45

FP(dB) = 20log10(10) + 20log10(2400) + 32.45

FPSL= 120.05 dB

Given Distance d= 10 km

Frequency f=5.8 GHZ

when the distance (d is in km) and the frequency (f is in MHz) , the following formula is used to calculate the FSPL

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45 (1)

The given frequency is in GHZ, so we have to convert it in MHZ to use the above formula,

Frequency=5800 MHZ

FPSL(dB) = 20log10(d) + 20log10(f) + 32.45

Substitute value of frequency and distance in equation (1),we get

FP(dB) = 20log10(d) + 20log10(f) + 32.45

FP(dB) = 20log10(10) + 20log10(5800) + 32.45

FPSL= 127.72 dB.

 FPSL(dB) Distance(km) 2.4 GHZ 5.8 GHZ 5 114.0336 121.698 10 120.05 127.72

GET GUARANTEED SATISFACTION OR MONEY BACK UNDER WIRELESS DATA LINK ASSIGNMENT HELP SERVICES OF EXPERTSMINDS.COM - ORDER TODAY NEW COPY OF THIS ASSIGNMENT!

Question 2: For the information given below, calculate the link budget analysis for the wireless system, which will involve calculating the following:

Distance: 5 km

Frequency: 5.8GHz

Tx power: +23dBm

Antenna gain is 24dBi

Assume negligible loss for cabling and connectors

Given Frequency = 5.8GHz

Link Type is given in Point-to-Point and Line-of-Sight

Given, the value of Transmission power is equal to +23dBm

Given, Antenna gain is equal to 24dBi

We have to assume negligible loss for both cabling and connectors

The Receiver Sensitivity is equal to -72dBm

The gain is calculated by using the following formula

Gains(dB)=Transmit Antenna gain+ Receiver Antenna Gain (2)

Given Same antenna is used at the transmitter and the receiver side, also given the link budget calculations will be the same as the link budget in both directions is expected to be symmetrical.

So that the gain will be,

Gains(dB)=24+ 24=48 dBi

The Received Power is calculated by using formula given in equation (2), which as follows

Received Power (dBm) = Transmitted Power (dBm) + Gains (dB) - Losses (dB) (2)

From the above table we can see that loss is equal to 121.698 dB when the distance is equal to 5km and the frequency is equal to 5.8 GHZ.

Substitute the value of Transmission power, Gain and loss in equation (2), we get

Received Power = 23 + 48 - 121.698

The Link Margin is calculated by using formula given in equation (3), which as follows, the link margin is obtained by subtracting receiver sensitivity from the received power,

Substitute the value of Received Power and Receiver sensitivity in equation (3), we get

NO PLAGIARISM POLICY - ORDER NEW WIRELESS DATA LINK ASSIGNMENT AND GET WELL WRITTEN SOLUTIONS DOCUMENTS WITH FREE TURNTIN REPORT!

Question 3: For the calculated Link Margin at 5Km what can you say about the availability/reliability of the link based on the following Table which shows the relationship between the available link margin and link availability as a percentage of time.

 Time Availability (Percentage) Link/Fade Margin 90 8 99 18 99.9 28 99.99 38 99.999 48  