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**SEHS3302 Dynamics and Vibrations Assignment Help**

Question 1. Taking east as the positive x-axis and north as the positive y-axis. A car runs to the southeast (south and 45° to the east) from rest with a uniform acceleration of 10 m/s 2 ; a truck runs to the north with a constant speed 150 m/s, try to find out the relative Displacement, Velocity, and Acceleration of the truck with respect to the car at 2s instant. (hints: 1. Build the coordinate system)

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After 2 seconds, the truck will be at 300 m and the car will be at 40 m.

Displacement is denoted by R, and given below:

R= √(A^(2 )+ B^(2 )-2AB Cos ?)

R= √(?40?^(2 )+ ?300?^(2 )-2*40*300* Cos 135)

R= √(1600+ 90000-24000* Cos 135)

R= 329.5 m

Now relative velocity can be calculated as

Velocity (v) = Distance (R)/time

V = 329.5/2

V = 164.75 m/s

And thus acceleration (a)

a = v/t

a = 164.75/2

a = 82.375 m/s2.

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